How Do They Calculate the 9 Degrees in the Force Diagram?

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SUMMARY

The calculation of the 9 degrees in the force diagram is derived from the inverse tangent function, specifically arctan(30/190), which confirms the angle's measurement. The discussion also addresses the confusion surrounding the 19 N force, indicating that while the components may not seem accurate, they can be approximated using the Pythagorean theorem, resulting in a magnitude of F = sqrt(130^2 + 30^2). Participants clarify that a radian calculator is unnecessary for this problem, as basic calculations can be performed using online tools.

PREREQUISITES
  • Understanding of trigonometric functions, particularly inverse tangent (arctan).
  • Familiarity with vector components and force diagrams.
  • Knowledge of the Pythagorean theorem for calculating magnitudes.
  • Basic proficiency in using online calculators for mathematical computations.
NEXT STEPS
  • Research the application of arctan in physics for resolving forces.
  • Study vector decomposition and its relevance in force analysis.
  • Explore the Pythagorean theorem in the context of physics problems.
  • Learn how to utilize online calculators effectively for trigonometric functions.
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and force analysis, as well as educators seeking to clarify vector resolution techniques.

circuscircus
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Homework Statement


http://img61.imageshack.us/img61/4585/8m1cdhx1.gif

I understood every except, How do they get the 9 degrees in part c?

Homework Equations





The Attempt at a Solution

 
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Look at the components of the resultant of the three forces: using an inverse tangent you should be able to find the angle it makes with the x axis. (Draw a right triangle.)
 
So then is arctan(30/190) 9 degrees?

(I don't have access to a radian calculator right now), also how do they get the 19N?
 
circuscircus said:
So then is arctan(30/190) 9 degrees?
Yes.
(I don't have access to a radian calculator right now), also how do they get the 19N?
You don't need a radian calculator. (If ever you don't have a calculator handy, Google has one.)

The 19 N makes no sense. But the components are close enough, so you should be able to figure the magnitude properly from that.
 
So the real F is sqrt(130^2+30^2) am I correct?
 
circuscircus said:
So the real F is sqrt(130^2+30^2) am I correct?
Where did the 130 come from?
 

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