MHB How do trigonometric functions and their inverses relate to each other?

xyz_1965
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Take any trig function, say, arcsin (x). Why is the answer x when taking the inverse of sin (x)?

Why does arcsin (sin x) = x?

Can it be that trig functions and their inverse undo each other?
 
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You have to be mindful of the one-to-one interval over which the inverse function is defined. For example:

$$\arcsin\left(\sin\left(\frac{5\pi}{6}\right)\right)=\frac{\pi}{6}$$
 
MarkFL said:
You have to be mindful of the one-to-one interval over which the inverse function is defined. For example:

$$\arcsin\left(\sin\left(\frac{5\pi}{6}\right)\right)=\frac{\pi}{6}$$

What? Can you explain further? Why is the answer pi/6?
 
xyz_1965 said:
What? Can you explain further? Why is the answer pi/6?

What domain do we use for the sine function such that we can define an inverse?
 
MarkFL said:
What domain do we use for the sine function such that we can define an inverse?

Domain: [-1, 1].
 
No, that's the range.
 
MarkFL said:
No, that's the range.

[-pi/2, pi/2]
 
xyz_1965 said:
[-pi/2, pi/2]

Yes...is $$\frac{5\pi}{6}$$ in that domain?
 
MarkFL said:
Yes...is $$\frac{5\pi}{6}$$ in that domain?

Yes, it is.
 
  • #10
xyz_1965 said:
Yes, it is.

No, it is outside that since:

5/6 > 1/2

What is $$\sin\left(\frac{5\pi}{6}\right)$$ ?
 
  • #11
MarkFL said:
No, it is outside that since:

5/6 > 1/2

What is $$\sin\left(\frac{5\pi}{6}\right)$$ ?

I just got home. Let me see: sin(5pi/6) = 1/2.
 
  • #12
xyz_1965 said:
I just got home. Let me see: sin(5pi/6) = 1/2.

Yes. Now what angle within the restricted domain returns that same value from the sine function?
 
  • #13
MarkFL said:
Yes. Now what angle within the restricted domain returns that same value from the sine function?

Using the unit circle, I found the angle to be pi/6.
 
  • #14
xyz_1965 said:
Using the unit circle, I found the angle to be pi/6.

Good, the puzzle is thus completed. 😁
 
  • #15
MarkFL said:
Good, the puzzle is thus completed. 😁

Wasted too much time solving this puzzle. If I do this for every problem, I'll never get to calculus 1.
 
  • #16
If you now understand how this works I'd say it was time well spent.
 
  • #17
MarkFL said:
If you now understand how this works I'd say it was time well spent.

I got to speed up this precalculus trek. It is on hold as I wait for my Michael Sullivan 5th Edition Precalculus textbook to arrive.
 
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