How Do Two Superposed Waves Result in Points of Zero Displacement?

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SUMMARY

The discussion focuses on the derivation of the resultant displacement from two superposed waves, represented by the equations y1=Ysin(kx-wt) and y2=Ysin(kx+wt). The resultant displacement is expressed as y = 2Y sin(kx) cos(-wt). It is established that displacement is zero when kx equals nπ, where n is an integer, leading to the conclusion that x = nπ/k represents all points of zero displacement.

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Homework Statement


given 2 waves y1=Ysin(kx-wt): y2=Ysin(kx+wt).
derive expression of resultant displacement and expression of x(for resultant) where displacement always zero


Homework Equations


y=y1+y2
sinA+sinB=2sin((A+B)/2)cos((A-B)/2)


The Attempt at a Solution


i solved first part:y= 2Y sin (kx) cos (-wt)
but i don't understand the 2nd part. does it mean y=0 when sin kx=0? mean x=0?
 
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Is x = 0 the only value of x at which sin(kx) = 0?
 
I had figure it out.displacement is directly related to sin kx.displacement is Zero when kx equal to n*pai
where n is integer.displacement always zero when x = n*pai/k.
 

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