How do we convert a summation to integration?

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Discussion Overview

The discussion revolves around the conversion of summations to integrals, specifically examining the conditions under which a summation of the form \(\sum x_i y_i\) can be represented as an integral. Participants explore the implications of this conversion in the context of mathematical functions and physical concepts like center of mass.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant questions whether the conversion from summation to integration should be \(\int x dy\) or \(\int y dx\), noting that they initially thought these forms were equivalent only for linear functions without constant offsets.
  • Another participant challenges the initial description of summation as an analog of integration, suggesting a more precise relationship: \(\sum x_i \Delta y_i \rightarrow \int x dy\) and \(\sum y_i \Delta x_i \rightarrow \int y dx\).
  • A different participant states that summation is used to find the area under the curve, while integration achieves the same result more efficiently.
  • One participant references the center of mass formula, highlighting the difference between discrete and continuous distributions, and notes the absence of 'delta' in the continuous case.
  • Another participant agrees that the formulas for discrete and continuous cases are fundamentally different and questions how one derives the continuous expression from the discrete one.
  • There is a discussion about the implicit meaning of the mass elements in the center of mass formula, indicating that while \(\Delta\) does not appear, it is inherent in the concept of small mass pieces summing to a total mass.

Areas of Agreement / Disagreement

Participants express differing views on the relationship between summation and integration, with some asserting that they are not directly analogous in all cases. There is no consensus on how to derive the continuous expression from the discrete case, and the discussion remains unresolved regarding the implications of these formulas.

Contextual Notes

Participants highlight the importance of understanding the conditions under which summation and integration can be equated, as well as the nuances involved in different mathematical representations, particularly in the context of physical applications like center of mass.

MacNCheese
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When converting a summation of the form

\sum x_i y_i

to integration, how do we know if it's

\int x dy

or

\int y dx

At first I thought they're equivalent but obviously that's only true for a linear function with no constant offset.

I kind of see integration as a better form of multiplication so I've always had trouble with the fact that multiplication is commutative but integration isn't. A little help?
 
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Your description of the summation as an analog of integration is not quite accurate.
∑xiΔyi -> ∫xdy
∑yiΔxi -> ∫ydx
 
Summation is used to find the area under the curve. Integration is same thing, but much faster.
 
Well if you look at something like center of mass, it's mentioned as (in wikipedia)

\frac {\sum m_i r_i} {\sum m_i}

for discrete particles and

\frac {1} {M} \int r dm

for continuous distribution. There's no 'delta' anywhere.
 
Yes, those are two completely different formulas. The first is NOT the Riemann sum leading to the second.
 
MacNCheese said:
Well if you look at something like center of mass, it's mentioned as (in wikipedia)

\frac {\sum m_i r_i} {\sum m_i}

for discrete particles and

\frac {1} {M} \int r dm

for continuous distribution. There's no 'delta' anywhere.
Although the symbol Δ doesn't appear, it is implicit in the meaning of mi which is a small piece of the mass, which sums to M.
 
HallsofIvy said:
Yes, those are two completely different formulas. The first is NOT the Riemann sum leading to the second.

Isn't it? Then how do we derive such an expression?

mathman said:
Although the symbol Δ doesn't appear, it is implicit in the meaning of mi which is a small piece of the mass, which sums to M.

Thanks, that helps.
 

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