How Do You Achieve Force Equilibrium on a Moving Object?

  • Thread starter Thread starter starhallie
  • Start date Start date
  • Tags Tags
    Equilibrium Force
AI Thread Summary
To achieve force equilibrium on a moving object with a velocity of 10 m/s in the (+x) direction, the system must balance the horizontal forces acting on it. The two forces, F1 at 225 N and F2 at 135 N, are applied at angles of 30 degrees and -75 degrees, respectively. The calculations show that a third force, F3, must be applied with a magnitude of approximately 230.492 N at an angle of 4.45 degrees with respect to the (-x) direction. This results in dynamic equilibrium, as the object maintains a constant velocity despite the forces acting on it. The analysis confirms that gravity can be ignored in this horizontal motion scenario.
starhallie
Messages
15
Reaction score
0

Homework Statement



A particular object is moving on a horizontal (x,y) plane with a velocity of 10 m/s in the (+x) direction. It is simulaneously acted upon by two horizontal forces. F1= 225 N at an angle of 30 degrees with respect to (+x) and F2= 135N at an angle of -75 degrees with respect to (+x). Find the magnitude and direction of a third applied force that will leave the system in a state of equilibrium. Is the equilibrium static or dynamic? Explain your answer.


Homework Equations



I only know how to get started on this... I need help o:)

The Attempt at a Solution



I understand that the y components are ignored since there is a constant velocity in this system and acceleration would therefore equal 0. I drew a free-body diagram with force of gravity pointing downard, normal force pointing up, and the two other force vectors. Now what?

Thank you for your help!
 
Physics news on Phys.org
In my opinion, we should not consider gravity force (at least, we don't receive its mass to compute mg). Just calculate 2 force in the horizontal plane to find the 3rd force to make object is in equilibrium.

x-axis
\sumFx = 0
F1(cos30)+F2(cos75)+F3x = 0
225(0.866)+135(0.259)+F3x = 0
F3x = -229.796 N

y-axis
\sumFy = 0
F1(sin30)+F2(sin75)=F3y = 0
225(0.5)+(135(0.966)+F3y = 0
F3y = 17.9N

magnitude
F3 = sqrt(F3x^2+F3y^2)
F3 = 230.492N

angle
F3 angle = arctan(F3y/F3x)
F3 angle = arctan(17.9/229.796) = 4.45 degrees with respect to (-x).
(or 175.55 degrees from +x axis)

System will be dynamic equilibrium with a constant velocity of 10 m/s in the (+x) direction
 
Sorry for the very late reply, pafala... thank you so much for your help on this problem. I truly appreciate it!
 
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Thread 'Correct statement about a reservoir with an outlet pipe'
The answer to this question is statements (ii) and (iv) are correct. (i) This is FALSE because the speed of water in the tap is greater than speed at the water surface (ii) I don't even understand this statement. What does the "seal" part have to do with water flowing out? Won't the water still flow out through the tap until the tank is empty whether the reservoir is sealed or not? (iii) In my opinion, this statement would be correct. Increasing the gravitational potential energy of the...
Back
Top