How Do You Apply Kirchhoff's Rules to a Series Circuit with Multiple Resistors?

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SUMMARY

This discussion focuses on applying Kirchhoff's Rules to analyze a series circuit with multiple resistors, specifically addressing a circuit with resistances of 1.75 ohms and 7.05 ohms. The participant successfully calculated the current through the circuit using Ohm's Law (V = IR) but struggled with the current division at the junction of the resistors. The correct approach involves using Kirchhoff's Current Law (KCL) to establish that the total current entering a junction equals the total current leaving, leading to the equations I1*R1 = I2*R2 and I1 + I2 = TotalCurrent.

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Homework Statement


http://img165.imageshack.us/img165/3182/73661395nq3.jpg
http://g.imageshack.us/img165/73661395nq3.jpg/1/


Homework Equations


V = IR


The Attempt at a Solution


I got the first part right, but the second part eludes me.

V = IR
I = V/R
I = 46.3 / 7.05
I = 6.567375887 A

Which seems way too simple and wrong anyway.
I'm not really sure how to analyze the voltage or the current when it splits at the 1.75 and 7.05 ohm junction. How would I apply Kirchoff's rules here?
 
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Arriving at that junction the current sees a 7.05 Ohm resistor (R1) and a resistance RAB (R2) which you calculated already.
So the current will split as I1*R1 = I2*R2
You know R1 and R2.
You know I1 + I2 = TotalCurrent.
And you know TotalCurrent = Voltage/RAB
 

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