How Do You Calculate Angular Acceleration of a Disk?

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SUMMARY

The discussion focuses on calculating the angular acceleration of a disk in a system involving two masses and ropes. The key equations derived include \(120 - T_1 = 12a_1\), \(T_2 - 40 = 4a_2\), and \(T_1 - 2T_2 = 4\alpha\), with the relationships \(a_2 = 2\alpha\) and \(a_1 = \alpha\). By substituting these relationships into the equations, users can solve for the tensions and accelerations effectively. The solution process is confirmed to be straightforward once the correct approach is established.

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  • Understanding of Newton's laws of motion
  • Familiarity with free-body diagrams
  • Basic knowledge of rotational dynamics
  • Ability to solve simultaneous equations
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  • Study the principles of rotational dynamics in detail
  • Learn how to apply Newton's second law to rotational systems
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Physics students, mechanical engineers, and anyone interested in understanding the dynamics of rotational systems and tension calculations in pulley setups.

jonnyboy
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[SOLVED] Angular acceleration of disk

For the system below, determine the tension in each rope, the linear acceleration of each mass and the angular acceleration of the disk. [tex]\ g=10 m/s^2[/tex]. Use [tex]\ I=4 kgm^2[/tex].

So far I have drawn the free-body diagram for m1 and m2
[tex]\ 120 - T_1 = 12a_1[/tex] and [tex]\ T_2 - 40 = 4a_2[/tex]
and have figured [tex]\ T_1 - 2T_2 = 4\alpha[/tex]
[tex]\ a_2 = 2\alpha[/tex]
[tex]\ a_1 = \alpha[/tex]
 
Last edited:
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jonnyboy said:
So far I have drawn the free-body diagram for m1 and m2
[tex]\ 120 - T_1 = 12a_1[/tex] and [tex]\ T_2 - 40 = 4a_2[/tex]
and have figured [tex]\ T_1 - 2T_2 = 4\alpha[/tex]
So far, so good!
[tex]\ a_2 = 2\alpha[/tex]
[tex]\ a_1 = \alpha[/tex]
Excellent. Now use this to rewrite [itex]a_1[/itex] and [itex]a_2[/itex] in terms of [itex]\alpha[/itex] in your first two equations. Then you'll have three equations and three unknowns, which you can solve.
 
Thanks. I've got it from there. Just didn't realize how easy it was once I had that.
 

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