How Do You Calculate Average Speed with Variable Acceleration?

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Homework Help Overview

The discussion revolves around calculating average speed in a scenario involving variable acceleration. Participants are exploring the relationship between distance, time, and speed, particularly in contexts where acceleration changes.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants are questioning the definitions of speed and average speed, discussing how to calculate total distance and total time. There are attempts to clarify the components involved in the calculations, including the need to sum distances and times.

Discussion Status

Some participants are providing hints and asking guiding questions to help clarify the problem. There is an acknowledgment of initial misunderstandings regarding the definitions and calculations, but no consensus has been reached on a specific solution.

Contextual Notes

Participants are considering the implications of variable acceleration and the need for numerical values to better understand the total time involved in the calculations. There is an indication that assumptions about the problem setup may need to be revisited.

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Homework Statement


In the file below.

Homework Equations


Speed= total distance over total time.
Acceleration = change of speed over time

The Attempt at a Solution


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I tought it is just E because of the first rule above. But then I doubt my answer since it moved with constant acceleration first then constant speed. However, I don’t see thant any of the choices fit. Can someone help?
 

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Your definition for speed is actually the definition for average speed. What is the total distance and what is the total time?
 
Sum of distance and sum of time?
 
What is the sum of the distances? How much time elapsed in covering those distances?
Hint: for total time, try replacing t1 and t2 with numerical values to get an idea of total time in letter variables.
 
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Is it not d1+d2 for total distance? Aha, the hint makes this clear; it is just t2.
Next time I will assume some values. Thanks a lot.
 
Well, I made the same mistake at first.
 
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