How Do You Calculate Charge on Capacitors in a Circuit?

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SUMMARY

The discussion focuses on calculating the charge on capacitors in a circuit with four capacitors connected between points a and b. The equivalent capacitance was determined to be 6.54μF, and the charges on the 24.0μF and 7.00μF capacitors were correctly calculated as 108μC and 84.0μC, respectively. However, the calculations for the 2.00μF and 14.0μF capacitors were incorrect, prompting requests for assistance in verifying the calculations. The voltage across the capacitors is consistently noted as ΔVab = 16.5V.

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Homework Statement



Four capacitors are connected as shown in the figure below:
2930121411_c18fe7cb68_o.png


The Attempt at a Solution



(a) Find the equivalent capacitance between points a and b.
I found it to be 6.54μF.

(b) If ΔVab = 16.5 V calculate the charge on the the 24.0 μF capacitor.
108 μF (correct)

(c) If ΔVab = 16.5 V calculate the charge on the the 7.00 μF capacitor.
84.0 μF (correct)

(d) If ΔVab = 16.5 V calculate the charge on the the 2.00 μF capacitor.
I got 24.0 but its not correct.

(e) If ΔVab = 16.5 V calculate the charge on the the capacitor C, which equals 14.0 μF.
Likewise here.

Any help on parts d and e is appreciated.
 
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You should start by checking your calculations for part(a); I get a slightly different answer than you. If you show me your work, I can show you where you went wrong.
 

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