How Do You Calculate Fret Placement and Overtones in Musical Instruments?

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Homework Help Overview

The discussion revolves around calculating fret placement and overtones in musical instruments, specifically focusing on a guitar string and an organ pipe. The original poster presents problems related to string length, frequency, and wavelength, as well as overtones in an organ pipe.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants explore relationships between frequency and length of strings, questioning how to calculate fret placement for different notes. They also discuss the calculation of overtones in an organ pipe, with some attempting to apply formulas related to wave properties.

Discussion Status

Some participants have offered guidance on using specific formulas to relate frequency and length, while others express confusion about their calculations. The discussion includes attempts to clarify concepts and explore different methods, but no consensus has been reached on the correct approach.

Contextual Notes

Participants mention specific constraints such as the length of the guitar string and the temperature affecting sound speed in air. There is also a sense of urgency due to impending deadlines for the homework.

jrd007
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1) An unfingered guitar string is 0.73 m long and is tuned to play E above middle C (330 Hz). (a) How from from the end of the string must a fret (and your finger) be placed to play A above middle C (440 Hz)? (b) What is the wavelength on the string of this 440-Hz wave? (c) What are the frequency and wavelength of sound in air at 20 degree's C by this fingered string? Answers: a) 0.18 m, b) 1.1 m c) 440 Hz and 0.78 m

I am really stuck. All I can figure is that you incorporate L = v/2f... and f = v/wavelength... help me, please.

2) How many overtones are present within the audible range for a 2.14-m-long organ pipe at 20 degree's if (a) it is open (b) it is closed. Answers: a) 248 overtones, 249 overtones

What I thought you could do was v/2L and v/4L... 343/(2 x 2.14) = 80 and 40... not correct.
 
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See if these examples help - http://www.glenbrook.k12.il.us/gbssci/phys/Class/sound/u11l5b.html

To get a higher pitch, one has to shorten the length of the string.

Try f1 * L1 = f2 * L2, where f is frequency, and then the finger is place x = L1 - L2, and I think you can handle it from here. :smile:
 
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So I would use.

.73 m x 330 Hz = L2 x 440 Hz.

L2 = .547 not the same as the answer 1...
 
Anyone else have a suggestion?
 
Can someone please help me with these problems? :( It is due soon.
 

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