Calculating Frequency Shift for Temperature Change in Musical Instruments

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SUMMARY

The discussion focuses on calculating the frequency shift for a guitar string and an organ due to temperature changes. The unfingered guitar string, measuring 0.70 m and tuned to E (330 Hz), requires the finger to be placed 0.525 m from the end to play A (440 Hz). Additionally, the speed of sound in air is influenced by temperature, with the formula v = √(γRT/M) indicating that sound speed varies with the square root of temperature in Kelvin. This relationship is crucial for understanding frequency shifts in musical instruments.

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  • Understanding of wave mechanics and frequency calculations
  • Familiarity with the speed of sound equations
  • Knowledge of temperature conversion to Kelvin
  • Basic principles of musical acoustics
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  • Learn about the effects of temperature on sound speed in different mediums
  • Explore the physics of musical tuning and pitch adjustments
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Musicians, acoustics engineers, physics students, and anyone interested in the interplay between temperature and sound frequency in musical instruments.

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Homework Statement


1. An unfingered guitar string is 0.70 m long and is tuned to play E above middle C (330 Hz). How far from the end of this string must the finger be placed to play A above middle C (440 Hz)?

2. An organ is in tune at 20 degrees C. By what fraction will the frequency be off at 0 degrees C?

Homework Equations



The Attempt at a Solution



1. I used the v=(freq)(wavelength) equation:
v = (330)(0.70) = 231 m/s
Then i plugged in 231 to figure out the distance for 440 Hz:
(231 m/s) = (440)x
x=.525 m
I'm not sure if my method is right, so please check that! thanks

2. Not sure about this one

Thanks for the help
 
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I think that's right.

For the second part,
v=\sqrt{\frac{\gamma RT}{M}} The temperature should be in Kelvin. Since there is no change in the gas, \frac{\gamma R}{M} are constant, and so the speed of sound varies with the square root of temperature. That should help you out.
 

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