How Do You Calculate Half-Life from an Exponential Decay Equation?

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Homework Help Overview

The discussion revolves around calculating half-life from the exponential decay equation Y=Ae-t/λ. Participants are exploring how to express half-life in terms of the parameters A and λ.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the relationship between time t and the decay constant λ, with attempts to manipulate the equation to find half-life. Questions arise about incorporating the parameter A into the half-life expression.

Discussion Status

Some participants have provided expressions for half-life, while others are questioning how to maintain the relationship with A and λ. There is an ongoing exploration of different formulations and interpretations of the decay equation.

Contextual Notes

Participants are navigating the constraints of expressing half-life in terms of both A and λ, with some noting that certain manipulations lead to the loss of λ in their equations.

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Homework Statement


Given Y=Ae-t/(lambda) find the half life in terms of A and lambda

Homework Equations



Y=Ae-t/(lambda)

The Attempt at a Solution


every time t is a multiple of lambda the relationship then becomes (lambda(n)=A/e^n), i can't figure out how that will relate, i also tried setting the equation to A/2 however that just canceled out the A. Need help!
I figured it out t(1/2)=ln(2)/lambda, however i don't know how to incorporate A into this
 
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Expression of radioactive is written as
A = Ao*e^-λt...(1)
As you have mentioned
t_1/2 = ln(2)/λ.
The equation (1) can be written as
A/Ao = e^-λt. or
Ao/A = e^λt
Take logarithm of both the side and fine the expression for λ. Put it in the t_1/2 equation.
 
rl.bhat if i put the expression into lambda in the t_1/2 equation then i lose the lambda, i need to express it in lambda and A
 
In that case
t_1/2 = ln(A/Ao)/λ
 

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