How Do You Calculate Horizontal and Vertical Asymptotes?

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Discussion Overview

The discussion revolves around the calculation of horizontal and vertical asymptotes for the functions provided by participants. It includes clarifications on function notation and the implications of denominator values.

Discussion Character

  • Technical explanation, Conceptual clarification, Debate/contested

Main Points Raised

  • Participants present two functions, f(x) = 2x + 3/x + 2 and f(x) = 5x/x^2 + 1, but there is confusion regarding their correct notation.
  • One participant questions what values of x make the denominator zero and whether any values should be ignored in the context of asymptotes.
  • Another participant emphasizes the importance of correctly writing the functions, suggesting that the intended forms are f(x) = (2x + 3)/(x + 2) and f(x) = x/(x^2 + 1).
  • Clarification is sought on the correct interpretation of the function notation, with a focus on distinguishing between different possible representations.

Areas of Agreement / Disagreement

There is no consensus on the correct forms of the functions, and participants express differing interpretations of the notation. The discussion remains unresolved regarding the proper calculation of asymptotes.

Contextual Notes

Limitations include potential misunderstandings in function notation and the need for clarity on the definitions of horizontal and vertical asymptotes.

poohbear1986
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asymptotes horizontal and vertical

f(x)= 2x+3/x+2


f(x)=5x/x^2+1
 
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What values of x makes denominator zero? Do you have to ignore anything?
 
Last edited:
In order to DO them right, first WRITE them right!

What you wrote is f(x)= 2x+(3/x)+ 2 and f(x)=(x/x^2)+ 1 but what you really MEANT was f(x)= (2x+ 3)/(x+ 2) and f(x)= x/(x^2+ 1).

How to do them? Start by looking up the definitions of horizotal asymptote and vertical asymptote.
 
do you mean f(x) = 2x + (3/x) + 2 and f(x) = (5x/x^2) + 1

or

do you mean f(x) = (2x + 3)/(x + 2) and f(x) = 5x/(x^2 + 1)

Please clarify...
 

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