poohbear1986 Messages 20 Reaction score 0 Thread starter Nov 2, 2007 #1 asymptotes horizontal and vertical f(x)= 2x+3/x+2 f(x)=5x/x^2+1
Antineutron Messages 74 Reaction score 0 Nov 2, 2007 #2 What values of x makes denominator zero? Do you have to ignore anything? Last edited: Nov 2, 2007
HallsofIvy Science Advisor Homework Helper Messages 42,895 Reaction score 983 Nov 3, 2007 #3 In order to DO them right, first WRITE them right! What you wrote is f(x)= 2x+(3/x)+ 2 and f(x)=(x/x^2)+ 1 but what you really MEANT was f(x)= (2x+ 3)/(x+ 2) and f(x)= x/(x^2+ 1). How to do them? Start by looking up the definitions of horizotal asymptote and vertical asymptote.
In order to DO them right, first WRITE them right! What you wrote is f(x)= 2x+(3/x)+ 2 and f(x)=(x/x^2)+ 1 but what you really MEANT was f(x)= (2x+ 3)/(x+ 2) and f(x)= x/(x^2+ 1). How to do them? Start by looking up the definitions of horizotal asymptote and vertical asymptote.
King Mickey Messages 5 Reaction score 0 Nov 4, 2007 #4 do you mean f(x) = 2x + (3/x) + 2 and f(x) = (5x/x^2) + 1 or do you mean f(x) = (2x + 3)/(x + 2) and f(x) = 5x/(x^2 + 1) Please clarify...
do you mean f(x) = 2x + (3/x) + 2 and f(x) = (5x/x^2) + 1 or do you mean f(x) = (2x + 3)/(x + 2) and f(x) = 5x/(x^2 + 1) Please clarify...