How Do You Calculate Impedance in a Series RLC Circuit?

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To calculate the impedance in a series RLC circuit with a 1170-ohm resistor, a 1.46 μF capacitor, and a 2.7 H inductor connected to a 350 Hz AC source, the formulas for inductive reactance (XL) and capacitive reactance (XC) are used. XL is calculated as 5937.61 ohms, while XC is determined to be approximately 0.000245 ohms, indicating a potential error in the XC calculation. The total impedance (Z) is computed using the formula Z=sqrt(R^2+(XL-XC)^2), resulting in an impedance of about 6051.79 ohms or 6.05179 kiloohms. The discussion highlights the importance of accurate calculations for XC, suggesting it should be closer to 100 ohms. Accurate impedance calculations are crucial for understanding circuit behavior.
Kris1120
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Homework Statement


A 1170 resistor, a 1.46 μF capacitor, and
a 2.7 H inductor are connected in series across
a 350 Hz AC source for which the maximum
voltage is 230 V.
Calculate the impedance of the circuit.


Homework Equations



Z=sqrt(R^2+(XL-XC)^20

XL=2*pi*f*L

XC=1 / (2*pi*f*C)

The Attempt at a Solution



XL= 2*pi*(350Hz)*(2.7H) = 5937.61

XC= 1 / (2*pi*350Hz* 1.46e-6 F) = .000245

Z= sqrt( 1170^2 + (5937.61 - 2.54e-4)^2) = 6051.79 ohms => 6.05179 kiloohms
 
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Your Xc calculation looks wrong... should be up closer to 100 Ohms or so...
 


awesome! thanks!
 
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