How Do You Calculate Initial Speed and Acceleration of a Slowing Truck?

Click For Summary

Homework Help Overview

The problem involves a truck that covers a distance of 45.0 m in 8.00 s while decelerating to a final speed of 2.60 m/s. Participants are tasked with finding the initial speed and acceleration of the truck.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss various equations related to motion, expressing uncertainty about how to find the initial speed and acceleration. Some suggest using average velocity, while others propose different kinematic equations. There is a focus on the need for known variables to apply these equations effectively.

Discussion Status

Several participants have offered guidance on which equations might be useful, with suggestions to solve for initial speed or acceleration first. There is an ongoing exploration of different interpretations of the problem, including a hypothetical scenario where the truck is speeding up instead of slowing down.

Contextual Notes

Participants note the challenge of working with unknown variables and the constraints of the problem setup. There is a recognition of the need for more information to apply certain equations effectively.

physics_geek
Messages
82
Reaction score
0
velocity & acceleration!

A truck covers 45.0 m in 8.00 s while smoothly slowing down to final speed 2.60 m/s.

a. the original speed?

b. the acceleration?

i have no idea how to do this
i thought i would use this formula

Vfinal = Vinitial + at...but i need to know the acceleration which i do not know how to find
 
Physics news on Phys.org


physics_geek said:
A truck covers 45.0 m in 8.00 s while smoothly slowing down to final speed 2.60 m/s.

a. the original speed?

b. the acceleration?

i have no idea how to do this
i thought i would use this formula

Vfinal = Vinitial + at...but i need to know the acceleration which i do not know how to find

Perhaps you can find a more appropriate equation that takes into account the time and distance and velocity?
https://www.physicsforums.com/showpost.php?p=905663&postcount=2
 


well every equation i see..requires that you know the velocity and acceleration...which is what I am trying to find

the only equation i think i can use is the average velocity...which would just be

45/8 = 5.625

i don't see how this helps

im totally lost
 


physics_geek said:
well every equation i see..requires that you know the velocity and acceleration...which is what I am trying to find

the only equation i think i can use is the average velocity...which would just be

45/8 = 5.625

i don't see how this helps

im totally lost

Well what about this one?

x = x_0 + v_0 t + (1/2) a t^2
 


yea i was thinking abt that one

but wat would i put in for acceleration?!?
 


Why don't you try using this formulahttps://www.physicsforums.com/latex_images/90/905663-3.png and this formula https://www.physicsforums.com/latex_images/90/905663-4.png together.

In the first equation solve for Vo then plug that equation in the second equation. You see?
 
Last edited by a moderator:


carltouss619 said:
Why don't you try using this formulahttps://www.physicsforums.com/latex_images/90/905663-3.png and this formula https://www.physicsforums.com/latex_images/90/905663-4.png together.

In the first equation solve for Vo then plug that equation in the second equation. You see?

Actually you should consider solving the second one first for acceleration.
Then use the first to give you your final V.
 
Last edited by a moderator:


LowlyPion said:
Actually you should consider solving the second one first for acceleration.
Then use the first to give you your final V.

Yea but if you do it that way, you still don't know Vo ? That's why I said solve for Vo and then plug in because then everything else can be filled in accept for a. then that's how you get acceleration.
 


carltouss619 said:
Yea but if you do it that way, you still don't know Vo ? That's why I said solve for Vo and then plug in because then everything else can be filled in accept for a. then that's how you get acceleration.

What if I said :
A truck covers 45.0 m in 8.00 s while smoothly speeding up from an initial speed of 2.60 m/s.

The a would be the same magnitude but different sign.
 
  • #10


LowlyPion said:
What if I said :


The a would be the same magnitude but different sign.

Oh wow interesting never thought of it like that. true
 
  • #11


wow..i would never have figured that out

thanks a lot guys
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 7 ·
Replies
7
Views
1K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 10 ·
Replies
10
Views
1K
Replies
20
Views
2K
  • · Replies 16 ·
Replies
16
Views
1K
Replies
3
Views
2K
Replies
3
Views
2K
Replies
68
Views
5K
  • · Replies 38 ·
2
Replies
38
Views
5K