How Do You Calculate Initial Velocity and Angle in Two-Dimensional Kinematics?

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To calculate the initial velocity and angle in two-dimensional kinematics, focus on the velocity components after the engines fire. The spacecraft's accelerations in the x and y directions are given, along with the final velocity components. The time of 871 seconds is not necessary for this calculation, as the problem does not involve distance. Instead, use vector addition to determine the change in velocity components (∆Vx and ∆Vy) to find the magnitude and direction of the initial velocity. This approach simplifies the problem and avoids unnecessary equations related to distance.
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Homework Statement



Useful background for this problem can be found in Multiple-Concept Example 2. On a spacecraft two engines fire for a time of 871 s. One gives the craft an acceleration in the x direction of ax = 6.00 m/s2, while the other produces an acceleration in the y direction of ay = 5.68 m/s2. At the end of the firing period, the craft has velocity components of vx = 5800 m/s and vy = 6420 m/s. Find (a) the magnitude and (b) the direction of the initial velocity. Express the direction as an angle with respect to the +x axis.


Homework Equations


most likely the use of the 4 main kinematics equations

v2=v1+at
v2^2=v1^2+2ad
x=1/2(v1+v2)t
x=v1t+1/2at^2


The Attempt at a Solution



basically i have no idea where to begin in this question, its computer question and I keep getting the incorrect answer, if anybody has suggestions how to begin this problem that would be nice, like what wud i do with that time of 871 s?
 
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zn23 said:
most likely the use of the 4 main kinematics equations

v2=v1+at
v2^2=v1^2+2ad
x=1/2(v1+v2)t
x=v1t+1/2at^2

Hi zn23! :smile:

You can forget equations involving x … there's no distance involved in this problem. :wink:

Hint: Find ∆Vx and ∆Vy, and then its' a simple vector addition problem . :smile:
 

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