Engineering How Do You Calculate Load Current Values in a Center-Tap Full Wave Rectifier?

AI Thread Summary
To calculate load current values in a center-tap full wave rectifier, it's essential to determine the maximum current (Im) first. This value is crucial for finding the peak, average, and RMS values of the load current, as well as the ripple factor and efficiency. Without a smoothing capacitor, the ripple factor will be higher due to the lack of voltage stabilization. Providing detailed calculations and showing the work done can help clarify the process. Understanding these concepts is vital for accurately analyzing rectifier performance.
snehil31
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Homework Statement
In a centre-tap full wave rectifier shown in the figure, forward resistance of each diode is 50 Ω .

Solve for
i) Peak, Average, RMS value of load current
ii) Ripple factor
iii) Efficiency
Relevant Equations
I(avg) = (2Im/pi) , I(RMS) = Im/(root 2)
[New poster has been reminded by the Mentors to show their work on schoolwork problems]

I have tried many times to solve this problem, but can't understand how to get the value of Im and hence cannot find the Peak & other values of the load current. Please help me to solve and find the Peak, Average, RMS value of load current as well as ripple factor and efficiency of the centre-tap full wave rectifier.

Note:- The figure is attached below.

4.png
 
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snehil31 said:
I have tried many times to solve this problem
Could you show us some of that work? Also, without any smoothing capacitor, what do you think the Ripple Factor will be?
 

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