How Do You Calculate Reactions at a Pin and Roller on an Inclined Beam?

Click For Summary
SUMMARY

The discussion focuses on calculating the reactions at a pin support (A) and a roller support (B) on an inclined beam subjected to a vertical load. The calculated reactions are Ax = 192 N, Ay = 180 N, and By = 642 N. Key equations utilized include the equilibrium equations for forces and moments, specifically addressing the vertical and horizontal forces at the supports. The beam's inclination angle is 22 degrees, which affects the vertical force resolution of the applied load.

PREREQUISITES
  • Understanding of static equilibrium principles
  • Knowledge of reaction forces at supports (pin and roller)
  • Familiarity with trigonometric functions for force resolution
  • Ability to apply moment equations in structural analysis
NEXT STEPS
  • Study the method of joints in static equilibrium
  • Learn about the analysis of inclined beams in structural engineering
  • Explore the application of trigonometry in resolving forces
  • Review examples of calculating reactions in different support configurations
USEFUL FOR

This discussion is beneficial for civil engineers, structural analysts, and students studying mechanics of materials, particularly those focusing on beam analysis and support reactions.

pleasehelpme6
Messages
62
Reaction score
0
Determine the reactions at the pin A and at the roller at B of the beam.

I honestly have no idea how to do this problem.
It gives the answers as...

Ax = 192 N
Ay = 180 N
By = 642 N

Please help.

better.jpg
 
Last edited:
Physics news on Phys.org
Heck, you've got to show something. Try listing the relevant equations. Note that the roller support can only provide vertical forces, not horizontal. The pin support can provide both. Use the equilibrium equations for forces and moments.
 
As phanthom jay said above you have a roller joint at point B so you have just a vertical reaction force Rby since it is a pin joint at point A you have reaction forces Ray and Rax. The beam is inclined at 22deg
The 500N force is resolved vertically giving 500/cos22

therefore
Rax=0
SUM horizontal forces
Ray + Rby=500/cos22

SUM moment of forces about Point B
Ray.8 - Rax.3.33=800

so i get
Rax=0N
Rbx=0N
Ray=-100N
Rby= 1434.7N
 

Similar threads

Replies
20
Views
4K
Replies
4
Views
4K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
Replies
10
Views
4K
Replies
8
Views
3K
  • · Replies 13 ·
Replies
13
Views
4K