How Do You Calculate Rope Tension with Friction and Constant Velocity?

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SUMMARY

The discussion focuses on calculating the tension in a rope when a block moves at a constant velocity of 2.3 m/s on a flat surface with a coefficient of kinetic friction (μk) of 0.40 and a weight of 9.8 N. Participants emphasize the importance of understanding the forces acting on the block, including friction (Fk), normal force (Fn), and gravitational force (Fg). A free body diagram is recommended to visualize these forces and determine the net force, which is crucial for solving the problem accurately.

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  • Knowledge of frictional forces and coefficients
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Homework Statement


The block moves at 2.3 m/s to the left (on a flat, horizontal surface). If μk, the coefficient of friction between the block and the floor, is .40, what is the tension in the rope? Also, the weight of the block is 9.8 N

Homework Equations



No equations were given... but I used Fk=μkFn

The Attempt at a Solution


2.3=.40Fn
Fn=5.75?
I googled how to find tension.. Some told me I needed three components: Ff, Fn, and Fg and some gave an acceleration for gravity. I don't understand how to go about this problem :/
 
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PerSempre said:

Homework Statement


The block moves at 2.3 m/s to the left (on a flat, horizontal surface). If μk, the coefficient of friction between the block and the floor, is .40, what is the tension in the rope? Also, the weight of the block is 9.8 N
What rope? Is there a rope pulling this block? Is the speed constant? What does that tell you?

No equations were given... but I used Fk=μkFn
You'll need that to figure out the friction force.

The Attempt at a Solution


2.3=.40Fn
Fn=5.75?
You set a speed (2.3 m/s) equal to a force. That makes no sense! Also, Fn is given! No need to calculate it.

Start by drawing a free body diagram of the block. What forces act? What's the net force on the block?
 

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