How Do You Calculate Tensions in a Dual-Block and Rope System?

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SUMMARY

The discussion focuses on calculating tensions in a dual-block and rope system where two 1.0 kg blocks are connected by a rope, and a second rope with a mass of 250 g hangs beneath the lower block. The entire system is accelerated upward at 3 m/s² by an external force F. The correct formulas for tension are established as T = g(mass of all things under it), leading to the need for accurate calculations of Tsub1 and Tsub2. Participants emphasize the importance of a diagram for clarity in solving the problem.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with tension in ropes and pulleys
  • Basic knowledge of free body diagrams
  • Ability to apply gravitational force calculations
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  • Review Newton's second law and its application in tension problems
  • Study free body diagram techniques for multi-body systems
  • Learn about the effects of acceleration on tension in rope systems
  • Explore examples of similar tension calculation problems in physics textbooks
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Homework Statement



The figure shows two 1.0 kg blocks connected by a rope. A second rope hangs beneath the lower block. Both ropes have a mass of 250 g. The entire assembly is accelerated upward at 3m/sec^2 by force F.

What are the following tensions:

1. The tension of the top of rope 1.
2. The tention of the bottem of rope 1.
3. The tension of the top of rope 2.

Includes the following diagram
[A]
|1

|2


Homework Equations


Fnet = 2.5*-9.8+F
T=g(mass of all things under it)

The Attempt at a Solution



Tsub1 = (.25+.25+1)g
Tsub2 = .25g

But these answers are wrong...
 
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Can't make sense of it with no diagram.
 

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