How Do You Calculate Tensions in a Suspended Mass System with Different Angles?

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SUMMARY

The discussion focuses on calculating the tensions in a suspended mass system with a weight of 1100N, supported by two strings at angles of 70 degrees and 80 degrees from the vertical. The equilibrium conditions are established using two equations: T1sin70 - T2sin80 = 0 for horizontal forces and T1cos70 + T2cos80 = 1100 for vertical forces. To solve for the tensions T1 and T2, one must isolate a variable in one equation and substitute it into the other, leading to a definitive solution for both tensions.

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Fusilli_Jerry89
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a 1100N mass is suspended from a string which is supported by two poles. One side makes an angle of 70 degrees with the vertical and the other side makes an angle of 80 degrees. Find the two tensions using components.

First I say that T1sin70-T2sin80=0 bcause the x forces have to be equal, otherwise the object would sway. Secondly I saw that T1cos70+T2cos80-1100=0 because the vertical components pushing upwards must equal the weight pulling downwards in order for the system to be in equilibrium. But now I do not know what to do after i get T1cos70+T2cos80=1100.
 
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You got 2 equations and 2 unknowns. Solve for a variable in one equation and plug it into the other
 

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