How Do You Calculate the Density of a Proton?

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To calculate the density of a proton, its diameter of 2.4 femtometers (fm) is used to find the radius of 1.2 x 10^-15 meters. The volume is calculated using the formula for the volume of a sphere, resulting in approximately 7.2 x 10^-45 cubic meters. The density is then determined by dividing the mass of the proton, 1.67 x 10^-27 kg, by the calculated volume. Despite following the correct formulas, the calculated density of 2.31 x 10^17 kg/m^3 is reported as incorrect, indicating a potential error in the calculations. The discussion highlights the challenges in accurately determining the density of subatomic particles.
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Homework Statement


A proton, which is the nucleus of a hydrogen atom, can be modeled as a sphere with a diameter of 2.4 fm and a mass of 1.67 multiplied by 10-27 kg. Determine the density of the proton.


Homework Equations


Volume=(4/3)pi*r^3
Density=mass/Volume


The Attempt at a Solution


I first got the radius: 1.2 * 10^-15
To get the volume i did: (4/3)*pi*(radius)^3 and i got 7.2 * 10^-45 as the volume
To get density i just jiust divided 1.67*10^-27/7.2*10^-45
and i got 2.31 *10^17 as the answer which is wrong.
 
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I get the same answer.
 
Delphi51 said:
I get the same answer.

o well. thanks for replying
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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