How Do You Calculate the Electric Field Between a Wire and a Cylinder?

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edwiddy
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This is for a stat mech class which randomly has a homework question with an electric field calculation. It's been a while, so I've forgotten a lot :(

Homework Statement



We have a wire of radius [tex]r_0[/tex] that is coincident with the axis of a cylinder with radius [tex]R[/tex] and length [tex]L[/tex]. The wire is maintained at positive potential $V$ with respect to the cylinder. Find the electrostatic field that exists at [tex]r, r_0 < r < R[/tex].

There is some thermodynamics stuff about the electrons forming a dilute gas, etc, but since we're given no information about the density and stuff I assume that they won't affect the electric field.

Homework Equations



Gauss's law: [tex]\Phi = \frac{Q}{\epsilon_0}[/tex]
Definition of potential: [tex]\int_{r_0}^{R} E dr = V[/tex]

The Attempt at a Solution



The issue is pretty straight forward. I plan on picking a cylinder with radius [tex]r[/tex] around the wire as the Gaussian surface for Gauss's law. However, I can't seem to use the potential with Gauss's law.

Thanks in advance.

EDIT: issues with tex.
 
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Let [tex]\lambda[/tex] be the linear charge distribution in the wire.

Use Gauss's Law to express the electric field in terms of [tex]r[/tex] and [tex]\lambda[/tex].

Then use this:

edwiddy said:
Definition of potential: [tex]\int_{r_0}^{R} E dr = V[/tex]


to determine the expression of [tex]\lambda[/tex] as a function of [tex]V[/tex].
 
Donaldos said:
Let [tex]\lambda[/tex] be the linear charge distribution in the wire.

Use Gauss's Law to express the electric field in terms of [tex]r[/tex] and [tex]\lambda[/tex].

Then use this:




to determine the expression of [tex]\lambda[/tex] as a function of [tex]V[/tex].

Gotcha gotcha, seems so obvious in hindsight, thanks.