How Do You Calculate the Electric Field from the Electric Potential V=4x²?

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SUMMARY

The electric potential is defined as V=4(x²) volts. To calculate the electric field from this potential, one must use the relationship E = -∇V, where E is the electric field and ∇V is the gradient of the potential. At the point (1m, 0m, 2m), the electric field can be determined by calculating the negative gradient of the potential function. The magnitude of the position vector r is √5, which is relevant for integration in this context.

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  • Understanding of electric potential and electric field concepts
  • Familiarity with vector calculus, specifically gradients
  • Basic knowledge of integration techniques
  • Ability to work with three-dimensional coordinate systems
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  • Study the concept of electric field and its relationship to electric potential
  • Learn about calculating gradients in three-dimensional space
  • Explore integration techniques relevant to vector fields
  • Review examples of electric field calculations from potential functions
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Kartik.
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The electric potential V at any point (x,y,z) in space is given by V=4(x^2) volts (all in meters). The electric field at the point (1m,0m,2m) is?

-->
dV= - (E.dr),
magnitude of r =sqrt(5),
V at the point will be 4, which => 4=-*integration sign*E.dr
how to solve this?
 
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Do it backwards. The electric field is equal to the negative gradient of the potential. Do you know what "gradient" is?

ehild
 
Definitely :P Thanks.
 

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