How Do You Calculate the Electric Field of a Finite Charged Slab?

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SUMMARY

The discussion focuses on calculating the electric field of a finite charged slab with a charge density defined as ρ = cx², where c is a constant. The problem specifies the slab extends from x = -3 to x = 3, and the electric field needs to be evaluated at x = 2. The key equation referenced is Gauss's law, expressed as ∫(E·dS) = (1/ε₀)∫(ρ dV), which requires integration over a closed surface to derive the electric field.

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  • Knowledge of volume integrals in three-dimensional space
  • Basic proficiency in calculus, particularly integration techniques
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Homework Statement



Need to calculate the electric field at x=2 for sheet of charge that extends from x=-3 and x=3 and is infinite in y and z. charge density rho=cx^2 c is a given numerical value

Homework Equations



integral(E.dS)= (1/epsilon)*volume integral(p dT)

The Attempt at a Solution



I'm completely at ends even where to start! Any help would be appreciated
 
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I would start by drawing a picture of the problem.

The integral you've given is Gauss's law. In order to solve it you need to integrate over a closed surface. So you need to think of an appropriate closed surface to integrate over. The volume integral will just be over the volume of the closed surface.
 

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