How Do You Calculate the Energy Stored in a Magnetic Field?

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SUMMARY

The discussion focuses on calculating the energy stored in a magnetic field within a superconducting solenoid with a magnetic field strength of 4.50 T, an inner diameter of 6.20 cm, and a length of 26.0 cm. The magnetic energy density is correctly calculated using the formula Ub = (B^2)/(2μ₀), resulting in 8.1 x 10^6 J/m³. For the total energy stored in the magnetic field, participants are guided to use the energy density and the volume of the solenoid, emphasizing the importance of including units in calculations.

PREREQUISITES
  • Understanding of magnetic fields and solenoids
  • Familiarity with the formula for magnetic energy density Ub = (B^2)/(2μ₀)
  • Knowledge of volume calculation for cylindrical objects
  • Basic arithmetic and unit conversion skills
NEXT STEPS
  • Calculate the total energy stored in the magnetic field using the formula E = Ub × Volume
  • Explore the concept of magnetic permeability (μ₀) and its significance in magnetic field calculations
  • Learn about the properties and applications of superconducting solenoids
  • Investigate the relationship between magnetic field strength and energy density in different materials
USEFUL FOR

Physics students, electrical engineers, and anyone interested in electromagnetism and energy storage in magnetic fields.

abot
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the problem reads... the magnetic field inside a superconducting solenoid is 4.50T. the solenoid has an inner diammeter of 6.20cm and length 26.0cm.
Determine (a) the magnetic energy density in the field. (b) he energy stored in the magnetic field with in the solenoid.

For (a) i use the formula Ub= (B^2)/(2Uo) and i get 8.1x10^6
Is this correct?

For (b) I am not quite sure what to do. I know i must use the length and diameter to find B. or maybe not

I need some guidance.

Thank You
 
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abot said:
For (a) i use the formula Ub= (B^2)/(2Uo) and i get 8.1x10^6
Is this correct?
Yes. (Check your arithmetic.)

For (b) I am not quite sure what to do. I know i must use the length and diameter to find B. or maybe not
Hint: The energy density that you found in (a) is the energy per unit volume.
 
If you had written the units for your first part, the second part would become obvious. Never leave out the units; they are essential.
 

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