How Do You Calculate the Equivalent Resistance in This Circuit?

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SUMMARY

The discussion focuses on calculating the equivalent resistance in a specific circuit configuration. The user initially attempted to calculate the equivalent resistance using the formula for parallel resistors but incorrectly excluded the 8 and 4 ohm resistors. A correct approach involves recognizing that the 30 ohm and 60 ohm resistors are in series, yielding an R1 of 90 ohms, while the 40 ohm and 10 ohm resistors also combine in series to give an R2 of 50 ohms. The final equivalent resistance can be calculated using the formula R_{eq} = (R1 * R2) / (R1 + R2).

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rootX
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Homework Statement


Find equivalent resistance in:
http://img135.imageshack.us/img135/585/62083770ay3.jpg

Homework Equations





The Attempt at a Solution


my
r_eq^-1 = (30+60)^-1+(40+10)^-1
this is wrong.
do i need to include 8 and 4 ohm resistors
 
Last edited by a moderator:
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rootX said:

Homework Statement


Find equivalent resistance in:
http://img135.imageshack.us/img135/585/62083770ay3.jpg

Homework Equations





The Attempt at a Solution


my
r_eq^-1 = (30+60)^-1+(40+10)^-1
this is wrong.
do i need to include 8 and 4 ohm resistors

Based on your drawing your equation looks correct. What answer did you get?

You can check your answer against this equation's results:

R_{eq} = \frac{R_1 \cdot R_2}{R_1 + R_2}

R1 would be 90 since 30 and 60 are in series and R2 would be 50 for the same reason.

CS
 
Last edited by a moderator:

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