How Do You Calculate the Final Kinetic Energy of a Jet-Powered Train?

[eagles_reciever]

Confusing problem? HELP please!

i am trying to solve this problem:

In the 1950s, an experimental train that had a mass of 2.60 X 10^4 kg was powered across a level track by a jet engine that produced a thrust of 5.25 X 10^5 N for a distance of 509 m. Assume that air resistance is negligible.

i am trying to find out the change in kinetic energy of the train and the final kinetic energy. however i cannot figure out what the velocity of the train is. Can anyone help please or provided an equation??


Thank you

 

[arildno]

You don't need it.
You are to find the CHANGE in the kinetic energy; that can be calculated by the work done by the force given.

 

[eagles_reciever]

You don't need it.
You are to find the CHANGE in the kinetic energy; that can be calculated by the work done by the force given.

im not understanding.. so find the change in work?

 

[eagles_reciever]

Speed equation?

how would i find the speed of the train in this problem:

In the 1950s, an experimental train that had a mass of 2.60 104 kg was powered across a level track by a jet engine that produced a thrust of 5.25 105 N for a distance of 509 m. Assume that air resistance is negligible.

The equation is d/t but i do not know what the time is. can anyone help please?

[Edit: Multiple threads merged. One thread per problem please! - Doc Al]

 

[Astronuc]

Well, if the train starts from rest, then the velocity for a given acceleration a over a distance x is given by

v² = 2 a x, where a is F/m, where F is the thrust and m is the mass being accelerated.

http://hyperphysics.phy-astr.gsu.edu/hbase/mot.html#mot1

http://hyperphysics.phy-astr.gsu.edu/hbase/mot.html#mot5

 

[Erythro73]

how would i find the speed of the train in this problem:

In the 1950s, an experimental train that had a mass of 2.60 104 kg was powered across a level track by a jet engine that produced a thrust of 5.25 105 N for a distance of 509 m. Assume that air resistance is negligible.

The equation is d/t but i do not know what the time is. can anyone help please?

If I assume the acceleration to be uniform, I would suggest to use the kinematic equation :
$V_{f}^{2}=V_{i}^{2}+2*a*d$

as you know d and a.

 

[arildno]

No, force times distance equals change in kinetic energy.