How Do You Calculate the Mass of a Steel I-Beam?

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Homework Help Overview

The discussion revolves around calculating the mass of a steel I-beam based on its dimensions and density. The original poster provides specific measurements for the beam and attempts to apply volume and mass formulas to determine the mass of a section of the beam.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the application of volume formulas, questioning the appropriateness of using certain dimensions for volume calculations. There is an exploration of the concept of area versus volume, particularly in relation to the cross-section of the beam.

Discussion Status

Some participants have pointed out potential errors in the original poster's calculations, particularly regarding the dimensions used for volume. There is an ongoing examination of the correct approach to finding the mass, with suggestions to clarify the definitions of area and volume in this context.

Contextual Notes

Participants note that the original poster's calculations may be affected by misunderstandings of the geometric properties of the beam. There is also mention of the necessity to ensure that the dimensions used are consistent with the physical characteristics of the beam.

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Homework Statement



a structural I-beam is made of steel. a view of its cross section and its dimensions are shown in the figure below. as seen in the figure, L=13.2cm, H=37.4cm, W=1.41cm. what is the mass of a section 1.25m long? the density of steel is 7.56x10^3kg/m^3

i attached a picture of the beam

Homework Equations



volume=LxHxW
m=dv

The Attempt at a Solution


1. i converted values to meters:
L=0.132m
H=0.374m
W=0.0141m

2.find the volume for the top and bottom rectangles ( they are both same measurements)
so... v=lxhxw
v=0.132mx0.0141mx1.25m
=2.3265x10^-3 m^3

since top and bottom rectangles are same so add
2.3265x10^-3 m^3+2.3265x10^-3 m^3= 4.653x10^-3 m^3

then found volume for middle rectangle
but first found its height 37.4-0.0141-0.0141=37.3718
v=lxwxh
37.3718mx0.0141mx1.25m=0.65m^3

3. m=dv so..
first add volumes= 4.653x10^-3m^3+0.65m^3=0.654
then 0.654m^3x7.56x10^3kg/m^3
=4949kg
and my answer is wrong ! :( please help ASAP i can't figure it out
take a look at my long solution and help me :)
 

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mynameiscool said:
volume=LxHxW
Yes, but only for a rectangular block, and the lengths L, H, W must be mutually perpendicular.
2.find the volume for the top and bottom rectangles
A rectangle has area, not volume. Just because the distances are called L, H and W doesn't mean that they plug naturally into a formula you know that has variables with those names. Variable names are just names; it's what they stand for that's important.
Find the area of the cross-section.
 
haruspex said:
Yes, but only for a rectangular block, and the lengths L, H, W must be mutually perpendicular.

A rectangle has area, not volume. Just because the distances are called L, H and W doesn't mean that they plug naturally into a formula you know that has variables with those names. Variable names are just names; it's what they stand for that's important.
Find the area of the cross-section.

area of the cross section as in Lxw ? i did that and i still got the wrong answer too
can you please explain step by step ?
 
In your calculation of the middle rectangle, you have used H = 37.4 rather than H = 0.374. This is why your calculation is incorrect.

BTW, you do not necessarily have to find the area of the cross section unless you are specifically asked for it. Multiplying the area of each individual rectangle by the length of the beam and adding the resulting volumes together will give the same answer as multiplying the area of the cross section by the length.
 

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