How Do You Calculate the Mass of m2 on an Inclined Plane with Friction?

[Bryon]

Homework Statement

Masses m1 and m2 are attached via a light string and pulley on an inclined plane as shown above. m1 has a value of 12 kg and moves down the plane at a constant velocity of 0.9 m/sec. The plane is tilted upwards at an angle of Θ = 26 °. The coefficient of static friction between m1 and the plane is μs = 0.24 and the coefficient of kinetic friction is μk = 0.19.

https://wug-s.physics.uiuc.edu/cgi/courses/shell/common/showme.pl?cc/DuPage/phys2111/fall/homework/Ch-06-Forces/friction_block_plane/plane_blocks.gif

What is the mass of m2?

Homework Equations

F = ma
f = uk(m1)g

The Attempt at a Solution

y1: m1sin(theta) - T - f = m1a
x1: N - mgcos(theta) = m1a

y2: T -m2g = m2a

Plugging in the numbers into y1 and then I set it equal to T. I then put that equation into y2 and I got 8.5kg for m2, and apparently this is incorrect. Any ideas?
Is my free body diagram correct? Thanks!

 

[kuruman]

y1: m1sin(theta) - T - f = m1a

You forgot the "g" in m1sin(theta)

x1: N - mgcos(theta) = m1a

The acceleration in a direction perpendicular to the plane is zero because, as it moves, the block does not jump off or sink into the plane. Use the correct N to find the force of friction f.

y2: T -m2g = m2a

This is OK.

 

[Delphi51]

y1: m1sin(theta) - T - f = m1a

Missing a factor of g in the first term. And of course a=0 so the right side is zero.