How Do You Calculate the Masses in a Two-Block System with a Tension of 18 N?

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Homework Help Overview

The discussion revolves around a two-block system connected by a string, where a vertical force is applied to the upper mass, resulting in a specific upward acceleration. Participants are tasked with determining the masses of the blocks based on the given tension in the string and the applied force.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore the application of Newton's Second Law to derive the masses, questioning the setup and the forces acting on each block. There is an attempt to solve for the upper mass using a derived equation, which leads to confusion regarding the expected relationship between the two masses.

Discussion Status

Some participants have provided guidance on setting up equations based on Newton's Second Law, while others express uncertainty about the correct application of forces. There is an ongoing exploration of the net forces acting on the blocks, with some participants questioning the assumptions made in the calculations.

Contextual Notes

Participants are working under the constraints of a homework assignment, which may limit the information available or the methods they can use. There is a noted confusion regarding the direction of forces and their contributions to the net force acting on the masses.

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Homework Statement



Two masses are joined together by a massless, inextensible string. A vertical force of 30 N applied to the upper mass gives the system a constant upward acceleration of 3.2 m/s^2.

If the tension in the connecting string is 18 N, what is the smaller of two masses?

If the tension in the connecting string is 18 N, what is the bigger of two masses?

F= 30 T=18 m=1.4 a=3.2 g=9.8

Homework Equations



F(net) = m*a

The Attempt at a Solution

The lower block can be solved for by:
T/(g+a) = M which is 1.4kg

but I can't get the value of the upper block(which I know should be smaller then 1.4)

M=(F+T-ma-mg)/(a+g) F=30 T=18 m=1.4 a=3.2 g=9.8
when I do this M= 2.3 but it should be smaller then 1.4 because I know 1.4 is the larger block.
 
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Call the bottom mass m2. You know its acceleration is 3.2 m/s2. You also know that the tension acting on it is 18 N. Can you set up a Newton's Second Law equation for that mass alone in which m2 is the only unknown?
 
johnec22 said:
M=(F+T-ma-mg)/(a+g) F=30 T=18 m=1.4 a=3.2 g=9.8
when I do this M= 2.3 but it should be smaller then 1.4 because I know 1.4 is the larger block.
You messed up the forces in that equation. (And what's "ma" doing in there?) Just use Newton's 2nd law directly, rather than plug into a derived equation that may or may not apply. It's much simpler and you'll know it's right.

What's the net force on the upper mass?
 
Isn't the net force 48 because both the 30 N and the 18 N of tension are moving in an upward direction.

48 = M(3.2-9.8)?

*edit: never mind I found the solution.. Thanks so Much!"
 
johnec22 said:
Isn't the net force 48 because both the 30 N and the 18 N of tension are moving in an upward direction.
No:
(1) The 30 N and 18 N forces act in different directions.
(2) The weight of the mass contributes to the net force.
 

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