How Do You Calculate the Minimum Cost of Constructing a Power Line?

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SUMMARY

The minimum cost of constructing a power line from a town to a mine, located 7.5 km from the town and 3 km from the mine, is calculated using the formula: Cost = Distance of road * 4500 + Distance through forest * 7500. The correct differentiation of the cost function reveals that the derivative of (7.5 - x)4500 is -4500, not -4500x. This correction is crucial for accurately determining the minimum cost of the power line.

PREREQUISITES
  • Understanding of calculus, specifically differentiation
  • Familiarity with cost optimization problems
  • Knowledge of basic geometry related to distance calculations
  • Ability to solve equations involving square roots
NEXT STEPS
  • Study optimization techniques in calculus
  • Learn about cost functions in engineering projects
  • Explore geometric interpretations of distance in optimization problems
  • Review examples of real-world applications of calculus in construction
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Students in engineering or mathematics, particularly those tackling optimization problems, as well as professionals involved in project cost estimation and construction planning.

Glissando
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Hey guys I know this questions has been posted before but I still can't seem to figure it out. Thanks a lot for your help (:

Homework Statement



A power line is to be constructed from a town to a mine that is located near a straight road going to the town. The point on the road closest to the mine is 7.5km from the town and 3km from the mine. The cost of building along the road is 4500$ per km, and through the forest to the mine, 7500$ per km. Find the minimum cost of the power line.


Homework Equations



Cost = Distance of road * 4500 + Distance through forest *7500

The Attempt at a Solution



C = Road(4500) + Forest (7500)
C = (7.5-x)4500 + 7500sqrt(x^2+9)
dC/dx = -4500x + .5(x^2+9)^-.5(2x)(7500)
dC/dx = -4500x + 7500x(x^2+9)^-.5
dC/dx = 500x [-9 + 15(x^2+9)^-.5]

0 = 500x[-9 + 15(x^2+9)^-.5]
0 = -9 + 15(x^2+9)^-.5
9/15 = (x^2+9)^-.5
x = -0.36

Thanks in advance (:
 
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Glissando said:
C = (7.5-x)4500 + 7500sqrt(x^2+9)
dC/dx = -4500x + .5(x^2+9)^-.5(2x)(7500)

You have not differentiated correctly.

The derivative of (7.5 - x)4500 is -4500, not -4500x.
 

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