How Do You Calculate the Moment of Inertia for a Disk Rotating About Its Edge?

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To calculate the moment of inertia for an 8 kg, 40 cm diameter disk rotating about its edge, the initial formula for inertia at the center is I = 1/2 MR^2. The parallel axis theorem is then applied to find the moment of inertia about the edge, which involves adding the inertia at the center (I_cm) to the product of mass (M) and the square of the distance (d) from the center to the edge. The correct formula becomes I = I_cm + Md^2, where d is the radius of the disk. This approach allows for accurate calculation of the moment of inertia for the specified rotation. Understanding these principles is crucial for solving related physics problems.
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Homework Statement


What is the moment of inertia of an 8 kg, 40 cm diameter disk for rotation through the edge of the disk?


Homework Equations


I = \frac{1}{2}MR^2


The Attempt at a Solution



Inertia at the center of the disk would be I = \frac{1}{2}MR^2, right? I'm not sure what the right equation for inertia at a point on the edge of a disk would be.
 
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Apply the parallel axis theorem to find the moment of inertia about a parallel axis a distance d from the centre of mass:

I = I_{cm} + Md^2AM
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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