How Do You Calculate the New Angular Speed of Coupled Wheels?

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SUMMARY

The discussion focuses on calculating the new angular speed of coupled wheels, specifically when one wheel rotates at 950 rev/min and a second wheel with twice the rotational inertia is coupled to it. The conservation of angular momentum is applied, leading to the equation Iw = (I + 2I)wf. The final angular speed (wf) is derived as wf = Iw/(3I), confirming that the new speed is one-third of the initial speed of the first wheel. The discussion emphasizes the importance of correctly applying the moment of inertia in the calculations.

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  • Knowledge of moment of inertia concepts
  • Familiarity with rotational dynamics equations
  • Basic algebra for solving equations
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1MileCrash
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Homework Statement



I really don't understand what to do next.

A wheel is rotating freely with an angular speed of 950rev/min on a shaft whose rotational inertia is negligible. A second wheel, initially at rest and with twice as much rotational inertia of the first is suddenly coupled on the shaft.

What is the new angular speed?

Homework Equations





The Attempt at a Solution



No external torques, so conservation of momentum must be observed.

I is the rotational inertia of the wheel spinning at 950rev/min;

2I is the rotational inertia of the wheel that is coupled.

wf is the final angular speed.


Iw = (I + 2I)wf

wf = Iw/(3I)

wf = w/2I

Right? I can substitute w in, but nothing to substitute in for I. How do I solve this problem?
 
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1MileCrash said:

Homework Statement



I really don't understand what to do next.

A wheel is rotating freely with an angular speed of 950rev/min on a shaft whose rotational inertia is negligible. A second wheel, initially at rest and with twice as much rotational inertia of the first is suddenly coupled on the shaft.

What is the new angular speed?

Homework Equations





The Attempt at a Solution



No external torques, so conservation of momentum must be observed.
Very nice. I like your way of thinking. :approve:

(By the way, I'm assuming here that when the problem statement says "rotational inertia," it's the same thing as "moment of inertia." I don't hear the term rotational inertia used very often. Even though moment of inertia is the more standard terminology, I'm guessing that your textbook/coursework uses rotational inertia to mean the same thing. Whatever the case, I, like you, am assuming that the I of the second wheel is twice that of the first, and the second wheel is initially at rest.)
I is the rotational inertia of the wheel spinning at 950rev/min;

2I is the rotational inertia of the wheel that is coupled.

wf is the final angular speed.


Iw = (I + 2I)wf
Once again, very nice. :approve:
wf = Iw/(3I)
Everything is on track and just fine. :approve:
wf = w/2I
Gwahhh! :bugeye: :cry: :eek:

Try that last simplification again. :smile:
 
Thanks, I got it this morning. Stupid, stupid error.
 

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