How do you calculate the probability of A or B when there is an intersection?

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To calculate the probability of A or B when there is an intersection, use the formula P(A or B) = P(A) + P(B) - P(A and B). Given P(A) = 0.4, P(B) = 0.5, and P(A and B) = 0.1, the correct calculation is 0.4 + 0.5 - 0.1, which equals 0.8. Simply adding the probabilities results in double-counting the intersection. This highlights the importance of accounting for overlapping probabilities in calculations. Understanding this principle is crucial for accurate probability assessments.
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Homework Statement



If P(A) = .4, P(B) = .5 and P(A and B) = .1, find P(A or B)

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The Attempt at a Solution



Why isn't the answer just .9, add the two probabilities together? The book says the answer is .8
 
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I got it now. I didn't see this equation

P(A or B) = P(A) + P(B) - P(A and B)

.4 + .5 - .1 = .8
 
That would work, if A and B were disjoint. But you have P(A and B) > 0, so there is some intersection. If you just take P(A or B) = P(A) + P(B), you count that intersection TWICE.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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