How Do You Calculate the Resultant Force and Its Direction from Two Vectors?

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To calculate the resultant force (FR) from two vectors (F1 and F2), first determine the x and y components of each force. For F1 at 250 lb and 60 degrees, and F2 at 375 lb and -45 degrees, add the respective components to find the total x and y components of FR. The magnitude of FR is calculated using the formula FR = sqrt(F1^2 + F2^2 - 2(F1)(F2)cos(θ)), resulting in approximately 393 lb. The direction can be found using the sine rule, and the angle must be adjusted based on the quadrant of the resultant vector. This approach simplifies the calculation using basic trigonometry and analytic geometry.
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My problem is to determine the magnitude and direction of the resultant force FR=F1+F2 and it's direction, measured counterclockwise from the positive x direction.

f1=250 lb @ 60 degrees from x
f2= 375 lb @ -45 degrees from x

Ok I got the magnitude by doing this:
(360-2(255))/2=-75 degrees

fr=sqroot of (250^2+375^2-2(250)(375)cos(75)
fr=393.188~ 393

then I got the angle by this:
375/sin x = 393.188/sin 75
x=67.1088
how do i get the resultant angle, what do I need to add to the 67 degrees?




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U have ur replies at Homework Section where the above pro should be
 
The easiest way to do it is by computing the x and y components of F1 and F2, add them respectively to get the x and y components of FR, and compute the magnitude and directions from these. It is a simple analytic geometry problem.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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