How do you calculate the total resistance?

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SUMMARY

The total resistance calculation for the circuit in Question 38 results in 92Ω. The circuit includes a combination of resistors: 60Ω, 15Ω, 20Ω, 10Ω, and 5Ω, with specific connections of series and parallel configurations. The 10Ω and 20Ω resistors are in series, yielding a resultant of 30Ω, which is then connected to the 15Ω resistor. Accurate calculations require careful attention to the arrangement of these resistors, particularly distinguishing between series and parallel connections.

PREREQUISITES
  • Understanding of series and parallel resistor configurations
  • Familiarity with Ohm's Law and resistance calculations
  • Ability to interpret circuit diagrams
  • Knowledge of equivalent resistance formulas
NEXT STEPS
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  • Study the application of Ohm's Law in complex circuits
  • Explore circuit simulation tools like LTspice for visualizing resistor configurations
  • Review common mistakes in resistance calculations to avoid errors
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Students studying electrical engineering, educators teaching circuit analysis, and hobbyists building electronic projects who need to understand resistor combinations and calculations.

Zoro
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Homework Statement


What is the Total resistance in Question 38.

Homework Equations

The Attempt at a Solution


I tried drawing the circuit again splitting up the series and parallel but i got the wrong answer. The answer is 92. Like i know that the 60 is parallen to 15 and the 15 is parallel to 10. The 15 and 5 are in series and the 20 and 10 are in series and maybe also 5. [/B]
 

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"3. The Attempt at a Solution "
 
Zoro said:

Homework Statement


What is the Total resistance in Question 38.

Homework Equations

The Attempt at a Solution


I tried drawing the circuit again splitting up the series and parallel but i got 93. The answer is 92. Like i did 40 + 40 + 10+ 1/((1/60)+(1/15) + 1/20 + 1/10 + 1/5)[/B]
You took all the 60 Ω, 15Ω, 20Ω, 10Ω, 5 Ω resistors parallel; they are not.
 
ehild said:
You took all the 60 Ω, 15Ω, 20Ω, 10Ω, 5 Ω resistors parallel; they are not.
So what now
 
The ammeter can be replaced by a single wire. How are the 10Ω and 20Ω resistors connected?
 
ehild said:
The ammeter can be replaced by a single wire. How are the 10Ω and 20Ω resistors connected?
Well, it doesn't say. It's just in series judging by the diagram
 
Zoro said:
Well, it doesn't say. It's just in series judging by the diagram
You need to use the diagram.
Yes, they are in series. What is their resultant? How that resultant is connected to the 15 Ω resistor?
 
ehild said:
You need to use the diagram.
Yes, they are in series. What is their resultant? How that resultant is connected to the 15 Ω resistor?
Resultant? like 10 + 20 = 30 ?
 
Zoro said:
Resultant? like 10 + 20 = 30 ?
Yes. Now you replace the 10Ω and 20Ω resistors with their series equivalent. How is that 30Ω resistor connected to the 15Ω resistor?
 
  • #10
ehild said:
Yes. Now you replace the 10Ω and 20Ω resistors with their series equivalent. How is that 30Ω resistor connected to the 15Ω resistor?
I did this earlier. Is it correct
 

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  • #11
Zoro said:
I did this earlier. Is it correct
The diagram is correct. What is the result?
 
  • #12
ehild said:
The diagram is correct. What is the result?
80 + 1/ (1/60 + (1/20) + (1/30) = 90 =/= 92
 
  • #13
Zoro said:
80 + 1/ (1/60 + (1/20) + (1/30) = 90 =/= 92
Yor calculation is wrong. How are the 30Ω and 15 Ω resistors connected?
 
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  • #14
ehild said:
Yor calculation is worong. How are the 30Ω and 15 Ω resistors connected?
wat
 
  • #15
Zoro said:
wat
?
I quit. Good luck.
 
  • #16
ehild said:
?
I quit. Good luck.
LOl. wtaf man. can you just stop beating around the bush and hit the turkey on the head already?
 
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  • #17
Forum rules don't allow us to just give you the answer. For why see..

http://tinyurl.com/os67nwp

Next step (as ehild said) is to figure out how the 30Ω and 15 Ω resistors are connected? Series? Parallel? Replace these two with their equivalent.
 

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