How Do You Calculate the Triple Integral of (x+5y) in a Bounded Region?

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SUMMARY

The discussion focuses on evaluating the triple integral of the function (x+5y) over a bounded region defined by the parabolic cylinder y=3x^2 and the planes z=9x, y=18x, and z=0. The calculated result of the integral is -797817.6, derived through specific bounds: 0 ≤ z ≤ 9x, 18x ≤ y ≤ 3x^2, and 0 ≤ x ≤ 6. The solution involves integrating the function (x+5y) with respect to z, y, and x sequentially, applying the appropriate limits for each variable.

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Homework Statement


Evaluate the triple integral of (x+5y)dV where E is bounded by the parabolic cylinder y=3x^2 and the planes z=9x, y=18x and z=0.


Homework Equations





The Attempt at a Solution



My solution is this...

27*6^5 /5 - 162*6^4 /4 + (45/2)*(9*6^6 /6 - 324*6^4 /4) = -797817.6

My steps are here:

Bounds:
0<= z<=9x
18x<= y <=3x^2
0<= x<=6

(x+5y)dzdydx
(x+5y)z
(9yx^2 + 45y^2x /2)dx
[27x^4 - 162x^3 + (45/2)*(9x^5 - 324x^3)]dx

EVALUATED FROM 0 TO 6
27x^5 /5 - 162x^4 /4 + (45/2)*(9x^6 /6 - 324x^4 /4)
 
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