How Do You Calculate Total Image Distance in a Dual Lens System?

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SUMMARY

The discussion focuses on calculating the total image distance in a dual lens system comprising a converging lens with a focal length of 10 cm and a diverging lens with a focal length of 15 cm. The object is positioned 30 cm to the left of the diverging lens, which is 60 cm to the right of the converging lens. The solution involves applying the lens formula, 1/f = 1/o + 1/i, to find the image distance formed by the converging lens, which then serves as the object for the diverging lens. The final calculation yields the total distance from the original object to the final image.

PREREQUISITES
  • Understanding of lens formulas, specifically 1/f = 1/o + 1/i
  • Knowledge of converging and diverging lens behavior
  • Ability to visualize and interpret optical diagrams
  • Familiarity with focal lengths and object/image distances
NEXT STEPS
  • Study the application of the lens formula in multi-lens systems
  • Learn how to draw ray diagrams for converging and diverging lenses
  • Explore the concept of effective focal length in combined lens systems
  • Investigate real-world applications of dual lens systems in optics
USEFUL FOR

Students studying optics, physics educators, and anyone interested in understanding the principles of image formation in multi-lens systems.

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Homework Statement

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A Converging Lens, with focal length of 10 cm, is 60 cm to the left of a Diverging Lens, with focal length 15 cm. The Object distance is 30 cm to the left of the Diverging Lens. What is the total distance between the starting object and the final image?


Homework Equations

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1/f = 1/o + 1/i


The Attempt at a Solution

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I tried to solve this problem, but I can't understand how to do it because it is a multiple lens problem, however, the object is in the middle of the two lenses. Any help?

(Need a Diagram as well)
 
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Diiyad said:
1. ... The Object distance is 30 cm to the left of the Diverging Lens. ...


The real object is to the left of the converging lens. It forms an image at the given distance of 30 cm from the diverging lens. This image is now the object for the diverging lens. The problem requires you to calculate the distance between the real object to the left of the converging lens and the final image formed by the diverging lens.
 

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