How Do You Calculate Total Impedance in a Mixed RLC Parallel Circuit?

Click For Summary
To calculate the total impedance in a mixed RLC parallel circuit, one must consider the resistive and reactive components. The resistance is given as R = 10^4 ohms, while the inductive reactance is X = 100 ohms, represented as +jX. Each capacitor contributes a negative reactance of -jX, balancing the inductor's positive reactance. The total impedance can be found by combining these components using the formula for parallel circuits, ensuring that the inductive and capacitive reactances cancel each other out. Understanding the circuit layout is crucial for accurate calculations.
trailtiger
Messages
1
Reaction score
0
Circuit analysis - PLEASE HELP!

Here is the question:

R= 10^4
X = 100 ohms

-----I I-----------I I------
I I
I I
I I
(INDUCTOR) (RESISTOR)
I I
I I
--------------------------

The inductor is +jX
The capacitors are each -jX

Find the total impedance for the circuit so that the impedance of the inductor has the same mag. but opposite sign as each capacitor.
 
Physics news on Phys.org
Actually, I can't understand your picture[/color]
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

  • · Replies 3 ·
Replies
3
Views
989
Replies
3
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 15 ·
Replies
15
Views
5K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 16 ·
Replies
16
Views
3K
  • · Replies 1 ·
Replies
1
Views
796
  • · Replies 14 ·
Replies
14
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K