How Do You Calculate Voltages and Power in a Complex Circuit?

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SUMMARY

The discussion focuses on calculating voltages and power in a complex circuit involving resistors. The user successfully simplified three parallel resistors to an equivalent resistance of 6Ω and calculated the source current (Is) as 0.5A. Using the current divider rule, the voltages across the 30Ω and 5Ω resistors were determined to be 3V and 0.5V, respectively. The power dissipated in the 6Ω resistor was calculated to be 1.5W.

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qpham26
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Homework Statement


(a) Find v1 and v2 in the following circuit. ( i assume that they are asking for voltage of 30Ω and 5Ω)
(b) Determine the power dissipated in the 6-Ω resistor.
https://sphotos-b.xx.fbcdn.net/hphotos-ash3/580277_498142810205239_1717053686_n.jpg

Homework Equations


Equivalent resistor equation.
Current divider

The Attempt at a Solution


simplified the 3 parallel resistors into Req = 6Ω
Find Is = 12V/ (12+6+6) = 0.5A
Back to original circuit, 30Ω || 25+5Ω => Req2 = 15Ω
Use current divider rule to find Current of eq2 = (10Ω x 0.5A)/(10+15Ω) = 0.2A

Use that to find I1 = 0.1A and I2=0.1A

so V1 = 0.1 x 30 = 3V
V2 = 0.1 x 5 = 0.5V

P6Ω = Is^2 x 6Ω = 1.5WTHanks for your time.
 
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