How Do You Construct Bijections Between Different Types of Intervals?

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SUMMARY

This discussion focuses on constructing bijections between different types of intervals, specifically the closed interval [w,x] to [y,z] and the half-open interval (w,x] to [y,z]. The key equation presented for the closed interval bijection is (z-y)/(x-w) * (f-w) + y, which is confirmed to be both injective and surjective, thus establishing a bijection. The participants clarify that "constructing" a bijection involves presenting the equation and demonstrating its one-to-one and onto properties, while also addressing the complexity of representing bijections for half-open intervals.

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Homework Statement



Let w,x,y,z be real #'s with w<x and y<z

Construct bijections
[w,x] <-> [y,z]
(w,x] <-> [y,z)

Homework Equations



The Attempt at a Solution



So for the closed interval bijection, I was trying to work with the following:

(z-y)/(x-w) * (f-w) + y where w,x,y,z are the #'s and f is the function variable.

If I'm not mistaken, this is injective and surjective, thus bijective.

One thing I was wondering is simply what it means to "construct" the bijection?? Does it just mean presenting the equation above and showing that it is 1-1 and onto? Or is there something more complex at work?

And for the (...] <-> [...) portion, I am at a loss. Can this be done in a regular function type format, or do I need to do it piecewise?

Thanks
Pete
 
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Welcome to PF!

Hi Pete! Welcome to PF! :smile:
panderse said:
One thing I was wondering is simply what it means to "construct" the bijection?? Does it just mean presenting the equation above and showing that it is 1-1 and onto? Or is there something more complex at work?

Yes, "construct" just means presenting an equation.
And for the (...] <-> [...) portion, I am at a loss. Can this be done in a regular function type format, or do I need to do it piecewise?

oh come on

imagine you're a three-year-old child and you're presented with two [) and (] -shaped bricks :rolleyes: :wink:
 

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