How Do You Convert a Transfer Function into Polar Form?

To convert your transfer function to polar form, you can use the following steps: 1. Rewrite the transfer function in terms of magnitude and phase: H(jw) = |H(jw)| * e^(j*phi) where |H(jw)| is the magnitude and phi is the phase 2. Find the magnitude of your transfer function: |H(jw)| = R / sqrt(R^2 + (1/wC)^2 + w^2L^2) 3. Find the phase of your transfer function: phi = arctan(-wRC / (1-w^2LC))In summary, to convert your transfer function to polar form, you can rewrite it in terms of magnitude
  • #1
Khesahn
5
0

Homework Statement


For my particular circuit I have found my transfer function already, which comes out to be:

H(jω)= R / [R+(1/jωC)+jωL]

I am now supposed to express it in polar form. I am confused on how I express such an expression in polar form. Could anyone give me some information on how to convert a transfer function to its polar form?

Homework Equations


None

The Attempt at a Solution


I have no solution for now as I am not sure on how to express an equation in polar form. The only thing I can think of is to replace the jω to change it to the s domain, but is this really polar form? I am confused, any help would be appreciated!
 
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  • #2
Polar form consists of a magnitude and an angle...
 
  • #3
Khesahn said:
The only thing I can think of is to replace the jω to change it to the s domain, but is this really polar form? I am confused, any help would be appreciated!

Your transfer function is a complex number that is a function of frequency (w). Polar form represents a complex number as a magnitude and phase.
 

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