Basic Z-Transform Transfer Function

Click For Summary
SUMMARY

The discussion focuses on deriving the transfer function H(z) for a digital filter defined by a difference equation. The participant expresses difficulty in rearranging the equation due to the presence of a constant term (0.7). A key insight provided is that the transfer function, defined as the ratio of output Y(z) to input X(z), remains valid regardless of initial conditions, similar to an R-C divider. This clarification enables a straightforward approach to finding H(z).

PREREQUISITES
  • Understanding of digital filters and difference equations
  • Familiarity with transfer functions in control systems
  • Knowledge of Z-transform concepts
  • Basic principles of R-C circuits
NEXT STEPS
  • Study the derivation of transfer functions from difference equations
  • Learn about the Z-transform and its applications in digital signal processing
  • Explore the concept of initial conditions in digital filters
  • Investigate R-C circuit analysis and its relation to digital filter design
USEFUL FOR

Students and professionals in electrical engineering, particularly those focusing on digital signal processing and filter design, will benefit from this discussion.

CoolDude420
Messages
199
Reaction score
9

Homework Statement


Hi,
I'm asked to find the transfer function for the following digital filter described by a difference equation

864d47d952.png


Homework Equations

The Attempt at a Solution


[/B]
Usually if there's no constant term (0.7) here, I can just rearrange in the form of Y(z)/X(z) to give me H(z). But I can't do that here. So what now?
 

Attachments

  • 864d47d952.png
    864d47d952.png
    44 KB · Views: 1,350
Physics news on Phys.org
CoolDude420 said:

Homework Statement


Hi,
I'm asked to find the transfer function for the following digital filter described by a difference equation

View attachment 225722

Homework Equations

The Attempt at a Solution


[/B]
Usually if there's no constant term (0.7) here, I can just rearrange in the form of Y(z)/X(z) to give me H(z). But I can't do that here. So what now?
You can do that.
The definition of a transfer function is output per input.
This is like an R-C divider with an initial charge on the C. The transfer function is the same irrespective of that charge.
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 14 ·
Replies
14
Views
2K
Replies
1
Views
3K
  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
8
Views
3K
Replies
1
Views
3K