How Do You Convert mg to kg?

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Discussion Overview

The discussion revolves around converting milligrams (mg) to kilograms (kg), focusing on the correct multiplication factor to use in the conversion process. Participants explore methods for unit conversion and share resources for further understanding.

Discussion Character

  • Homework-related, Mathematical reasoning

Main Points Raised

  • One participant asks for clarification on whether to multiply 1250 mg by 10^-3 or 10^-6 to convert to kg.
  • Another participant shares a link to Wolfram Alpha as a tool for conversion, suggesting it is effective.
  • A third participant expresses appreciation for Wolfram Alpha's utility.
  • A different participant explains a method of "multiplying by 1" to demonstrate the conversion process, detailing the steps to arrive at the conversion of 1250 mg to kg as 1250 x 10^-6 kg.
  • This participant also raises a concern about the transparency of the conversion process used by Wolfram Alpha.

Areas of Agreement / Disagreement

There is no consensus on the preferred method for conversion, as participants present different approaches and resources without resolving the initial question.

Contextual Notes

Some participants provide links to external resources, but there is a lack of clarity on the underlying assumptions in the conversion process. The discussion does not fully address potential misunderstandings about metric prefixes.

Who May Find This Useful

Individuals seeking assistance with unit conversions, particularly students or those new to the topic of metric measurements.

r-soy
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Hi

I want help to convert mg to kg

ex: 1250mg --- > kg

Are we multiply 1250mg X 10^-3

or multiply 1250mg X 10^-6


I want your help >>
 
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wolframalpha's real good!
 
One way that I've found helps students that are new to unit conversions understand is called "multiplying by 1" In any expression, I can multiply by 1 as many times as I want without changing the answer. To see how this works, let's take you question, as follows:
[tex]1250 mg = 1250 mg \frac{1 g}{1000 mg} \frac{1kg}{1000g} = \frac{1250 kg}{10^6} = 1250 \times 10^{-6} kg[/tex]

Does this help? The problem with Wolfram Alpha is that, while it works, you don't usually know what it is doing.
 
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