How Do You Convert Sound Pressure from Decibels to Force in Newtons?

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SUMMARY

The discussion focuses on converting sound pressure levels, specifically 160 dB, into measurable force in Newtons. It establishes that 160 dB corresponds to 0.290 PSI or 2000 Pascal. The conversion to force is contingent upon the surface area, where 0.290 PSI over 1 square inch equals 0.290 lbs, while over 10 square inches equals 2.90 lbs. The conversation also highlights the importance of understanding the context of force application, whether on the sound emitter, the air, or an object at a distance.

PREREQUISITES
  • Understanding of sound pressure levels and decibels
  • Knowledge of pressure units, specifically PSI and Pascal
  • Basic physics concepts related to force and area
  • Familiarity with the mechanics of sound emitters, such as speaker cones
NEXT STEPS
  • Research the relationship between sound pressure and force using the formula F = P × A
  • Explore the effects of sound pressure on different materials and their failure thresholds
  • Investigate the dynamics of sound wave propagation in sealed environments
  • Learn about measuring sound pressure levels using tools like SPL meters
USEFUL FOR

Acoustics engineers, sound designers, physicists, and anyone involved in the study of sound pressure effects on materials and structures.

XoticXJ
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I am trying to figure out how to convert the pressure from a low frequency sound wave at high decibel levels in short bursts, to a measurable force, such as "proper acceleration".
So far I have gathered that 160DB is equivalent to .290 PSI or 2000 Pascal, I am just having a very difficult time trying to convert that into a product of Force. I believe that this kind of pressure exerted on an object with a high sensitivity of failure due to initial shock, will ultimately fail however, I am trying to back that idea up with measurable data, and not by JUST physical, real world, testing.
 
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I am by no means an expert -- but it seems to me calculating the force requires knowledge of the surface area involved. Since PSI means "pounds per square inch", .290 PSI over 1 square inch = .290 lbs, whereas .290 PSI over 10 square inches = 2.90 lbs.

That's the simple answer -- but I suppose it would also depends on whether you mean the force acting on the sound emitter (force on a speaker cone), the force exerted by the sound emitter (speaker cone's force on the air), or the force on an object at a distance from the sound emitter (force of air pressure on your eardrum).
 
I am trying to determine the impacting forces on an object(s) when placed inside a sealed chamber, which is pressurized by multiple large diameter speakers. I took a quick measurement, and while one objects surface area is quite small at only 23"^2in (6.67lbs of force) the other is 143^2in. (41.47lbs of force). Thx for trying to help with this small "insignificant" problem.
 

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