How Do You Derive the Compton Equation?

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SUMMARY

The discussion focuses on deriving the Compton equation, specifically the relationship between the wavelengths before and after scattering, represented as λ' - λ = h/mc (1 - cosθ). Participants detail their attempts to apply conservation of momentum and energy principles, leading to various equations involving Planck's constant (h), mass (m), and the speed of light (c). The conversation highlights common pitfalls in the derivation process and encourages collaboration for error correction.

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  • Understanding of the Compton effect and its significance in quantum mechanics.
  • Familiarity with conservation laws in physics, particularly momentum and energy.
  • Knowledge of wave-particle duality and the relationship between energy and wavelength (E = hf).
  • Basic proficiency in algebra and trigonometry for manipulating equations.
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  • Study the derivation of the Compton equation in detail using quantum mechanics textbooks.
  • Learn about the implications of the Compton effect in photon interactions with matter.
  • Explore advanced topics in quantum mechanics, such as wave-particle duality and scattering theory.
  • Practice solving problems related to conservation of momentum and energy in particle physics.
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Students of physics, particularly those studying quantum mechanics, educators teaching the Compton effect, and researchers interested in photon-matter interactions.

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Homework Statement



Derive the compton equation.

Homework Equations


\lambda` - \lambda = h/ mc (1 - cos\theta)
E = hf = hc/\lambda




The Attempt at a Solution


Okay, I'm sorry this is so long, I'll try and make it as concise as it is possible for a whole blather of random crap to be :]

Conservation of momentum components:
h/\lambda = h/\lambda`(cos\theta) + Pe(cos\psi)
0 = h/\lambda`(sin\theta) - Pe(sin\psi)

After some combining, squaring, and the like (getting rid of \psi):
Pe2 = (h/\lambda)2 - (h/\lambda`)2cos2\theta + (h/\lambda`)2sin2\theta - (h/\lambda)(h/\lambda`)cos\theta


E2 = p2c2 + ER2
So
P2 = (E2 - ER2)/c2

So I plug that into my momentum (I'm not going to write the righthand side of the equation while i show what I did w/ that)

(E2 - ER2)/c2 = ...
((hc/\lambda)2 - (mc2)2)/c2 = .
I tried to get rid of the denominator 'c'...
(h/\lambda)2 - m2c2 = ...

(m2c2\lambda)/h = \lambda/\lambda` - h/\lambda`cos\theta

After some more fiddling I get to this:

\lambda` = h/m2c2 - (h/\lambda)(h/m2c2)cos\theta

It's kind of close but not really... I can write out all the steps I made if that is necessary, but I'm kind of hoping I made one nice, simple-to-fix error that is glaringly obvious to the more experienced :)

Thank you :)
 
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Hi latitude! :smile:

(have a lambda: λ and a theta: θ and a psi: ψ :wink:)
latitude said:
Pe2 = (h/\lambda)2 - (h/\lambda`)2cos2\theta + (h/\lambda`)2sin2\theta - (h/\lambda)(h/\lambda`)cos\theta

eugh :cry:

the first - should be a + :wink:
 

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