The discussion focuses on determining critical points from the derivative of the function f(x) = x³ - x² + 5. The derivative calculated is f'(x) = 3x² - 2x. To find critical points, one must set the derivative equal to zero and solve for x, leading to the equation 3x² - 2x = 0. This results in critical points at x = 0 and x = 2/3 after factoring.
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What does your textbook say about finding critical points?n.a.s.h said:Homework Statement
find the derivative and critical points of the function
f(x)= x^3-x^2+5
Homework Equations
The Attempt at a Solution
I tried to find the derivative: 3x^2-2x but I am not sure how to find the critical points from here...