How Do You Determine the Acceleration and Tension in a String and Pulley System?

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To determine the acceleration and tension in a string and pulley system with blocks A (4kg), B (10kg), and C (2kg), it is essential to analyze the forces acting on each block using free body diagrams (FBDs). The direction of movement must be assumed initially; for instance, if block A is assumed to move down, it can be treated as positive in the equations. The tension in the string can vary depending on the configuration, and it is important to establish the correct relationships between the blocks. If the initial direction assumption is incorrect, the resulting acceleration will simply have a negative sign. Understanding the system's dynamics requires careful consideration of the forces and the chosen direction of motion.
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Homework Statement



The masses of blocks A,B, and C are 4kg, 10kg and 2kg respectively. Knowing that P=0 and neglecting the masses of the pulleys and the effects of friction, determine a) the acceleration of each block and the tension in the chord.

Homework Equations



Fnet=ma

The Attempt at a Solution


I know that we have to draw FBD's for each block and then figure out the equations of each Fnet. But first, how do you know the direction that this system will move? Because for example, if you know that block A is moving down, we can assume down is positive and its equation will be
ma=mg-2T (because we denote down as positive)? Also, for block B, will the tension be 4T, since it's connected to four strings?
I am confused about how system works.

Thanks!

Physics Problem Set.jpg
 
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Just pick directions that you think the masses will accelerate and then write out you equations accordingly. If you picked the wrong direction the acceleration will have a minus sign in the end.

See,
 

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Oh, okay thanks for the diagram! What is y and V though?
 
y_2, y_4, and y_10 label the distances the masses move and V_2, V_4, and V_10 are the velocities of those masses. The directions chosen are my guess as to which way the masses will move.

Good luck!
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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