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How do you differenciate Log2(1-2x)

  1. Nov 8, 2008 #1
    1. The problem statement, all variables and given/known data
    So its log(base2)(1-2x)


    2. Relevant equations



    3. The attempt at a solution
    I understand that derivative of log(base:a)x equals 1/xlna. However, using (1-2x) for x and 2 for a I got 1/(1-2x)ln2. Of course, i have to use the chain rule, which turns out to be -2. So my final answer is -2/(1-2x)ln2. However, it seems like that is incorrect. please help me.
     
  2. jcsd
  3. Nov 8, 2008 #2

    Mark44

    Staff: Mentor

    Your answer looks fine to me, although it could also be written it as 2/[(2x - 1) ln 2]
     
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